A flat-bottomed test-tube with some lead shots in it floats upto a depth of 3.2 cm in a liquid and 2.4 cm in water. Find the relative density of the liquid.

0.24

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0.75

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0.1

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0.5

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Solution

The correct option is B 0.75
$\begin{matrix} Mass of liq displaced = Volume displaced \times density of liquid mass of water displaced = A \times 2.4 \times d_{1} Mass of (liquid displaced = A \times 3.2 \times d_{2} \end{matrix}$

$\begin{matrix} mass of water and liquid displaced are equal A \times 2 \cdot φ d_{1} = A \times 3 \cdot 2 d_{2} \end{matrix}$

$\begin{matrix} \frac{d_{2}}{d_{1}} = \frac{2.4}{3.2} = 0.75 Relative densety of liquid = 0.75 \end{matrix}$

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A flat-bottomed test-tube with some lead shots in it floats upto a depth of 3.2 cm in a liquid and 2.4 cm in water. Find the relative density of the liquid.

The correct option is B 0.75 Mass of liq displaced = Volume displaced×density of liquid mass of water displaced = A×2.4×d1 Mass of (liquid displaced =A×3.2×d2 mass of water and liquid displaced are equal A×2⋅φd1=A×3⋅2d2d2d1=2.43.2=0.75 Relative densety of liquid =0.75