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Standard XII

Physics

Shear Stress

A flat plate ...

Question

A flat plate of area 10cm $^{2}$ is separated from a large plate by a layer of glycerine $1 m m$ thick.If the coefficient of viscosity of glycerine is 20 poise, the force required to keep the plate moving with a velocity of $1 c m$ per sec is :

80 dyne

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200 dyne

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800 dyne

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2000 dyne

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Solution

The correct option is A 2000 dyne
Force required = $η A \frac{d v}{d y}$
Now, $\frac{d v}{d y} = \frac{10 \times 1 c m / s}{1 c m} = 10 / s$
So, force to keep plate moving = $10 \times 10 \times 20$ dyne = $2000$ dyne

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A flat plate of area 10cm2 is separated from a large plate by a layer of glycerine 1mm thick.If the coefficient of viscosity of glycerine is 20 poise, the force required to keep the plate moving with a velocity of 1cm per sec is :

The correct option is A 2000 dyneForce required = ηAdvdyNow, dvdy=10×1cm/s1cm=10/sSo, force to keep plate moving = 10×10×20 dyne = 2000 dyne

A flat plate of area 10cm $^{2}$ is separated from a large plate by a layer of glycerine $1 m m$ thick.If the coefficient of viscosity of glycerine is 20 poise, the force required to keep the plate moving with a velocity of $1 c m$ per sec is :

The correct option is A 2000 dyne
Force required = $η A \frac{d v}{d y}$
Now, $\frac{d v}{d y} = \frac{10 \times 1 c m / s}{1 c m} = 10 / s$
So, force to keep plate moving = $10 \times 10 \times 20$ dyne = $2000$ dyne