A flat square sheet of charge ( side 50 cm) carries a uniform surface charge density. An electron 0.5 cm from a point near the center of the sheet experiences a force of 1.8 * 10^-12N directed away from the sheet. Determine the total charge on the sheet.

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Solution

Since it is a sheet of charge, by Gauss' Law, electric field is σ/2ε

Given F = 1.8 x 10^-12 N, q = 1.6 x 10^-19

we get electric field = F/q = 1.125 x 10⁷ N/C

Equate this,

σ/ε = 1.125 x 10⁷

^{E= 8.85 ×10^-12}

We get σ = 9.95 x 10^{-5

A= 50×50×10^-4 metre^2}

So charge on sheet = Q = σA = 2.4875 x 10^-5 C

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A flat square sheet of charge ( side 50 cm) carries a uniform surface charge density. An electron 0.5 cm from a point near the center of the sheet experiences a force of 1.8 * 10-12 N directed away from the sheet. Determine the total charge on the sheet.

A flat square sheet of charge ( side 50 cm) carries a uniform surface charge density. An electron 0.5 cm from a point near the center of the sheet experiences a force of 1.8 * 10^-12N directed away from the sheet. Determine the total charge on the sheet.