A flat, square surface with sides of length L is described by the equations x=L,0≤y≤L,0≤z≤L The electric flux through the square due to a positive point charge q located at the origin (x=0,y=0,z=0) is:
A
q4ϵ0
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B
q6ϵ0
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C
q24ϵ0
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D
q48ϵ0
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Solution
The correct option is Cq24ϵ0
Total flux linked with the cube shown in figure due to charge placed at its corner =(q8ϵ0) (one-eighth part of the cube with centre at origin)
Now, this total flux passes through only 3 faces of the cube. Hence, flux passing through square regionin question ϕ′=(q8ϵ0)3=q24ϵ0