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Question

A flat, square surface with sides of length L is described by the equations x=L,0yL,0zL
The electric flux through the square due to a positive point charge q located at the origin (x=0,y=0,z=0) is

A
q4ε0
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B
q6ε0
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C
q24ε0
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D
q48ε0
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Solution

The correct option is C q24ε0
Imagine a charge q at the centre of a cube of edge length 2L (Fig.). Then
ϕ=qϵ0
Here, the square is one 24th of the surface area of the imaginary cube, so it intercepts 1/24 of the flux. That is,
Φ=q24ϵ0.
1575521_158262_ans_19fd4e0324784088802758b7ff80df96.jpg

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