A flat, square surface with sides of length L is described by the equations x=L,0≤y≤L,0≤z≤L The electric flux through the square due to a positive point charge q located at the origin (x=0,y=0,z=0) is
A
q4ε0
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B
q6ε0
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C
q24ε0
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D
q48ε0
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Solution
The correct option is Cq24ε0 Imagine a charge q at the centre of a cube of edge length 2L (Fig.). Then ϕ=qϵ0 Here, the square is one 24th of the surface area of the imaginary cube, so it intercepts 1/24 of the flux. That is, Φ=q24ϵ0.