Question

A flexible chain has a length $l$ and mass $m$. It is lowered on the table top with constant velocity $v$. Find the force that the chain exerts on the table as a fraction of time.

Answer 1

let situation of chain be like this.

exerts will be due to x length only

let s is mass per unit length

$s=M/L$

on x length ,gravitional force is sxg

due to this exerts force generated and is equal to this.

$f=sxg$

we have to calculate df/dt

$f=sxg$

$df/dt=sgdx/dt$

$df/dt=sgv$

$df/dt=\left(M/L\right)\times g\times v$