Question

Question 87

A floor is 4.5 m long and 3.6 m wide A 6 cm square tile costs Rs. 23.25.
What will be the cost to cover the floor with these tiles?

Answer 1

Length of floor = 4.5 m and width of floor = 3.6 m
Area of floor = length $\times$ Breadth $=4.5\times 3.6m^2[\because width=breadth=3.6m]$
Side of square tile $=6cm=\frac{6}{100}=0.06m$
Area f one tile $=(side{)}^2=0.06\times 0.06m^2$
NUmber of tiles $\frac{Areaoffloor}{Areaofonetile}=\frac{4.5\times 3.6}{0.06\times 0.06}=4500$
$\because$ cost fo 1 tile = Rs. 23.25
$\therefore$ cost of $4500tilesRs.23.25\times 4500=Rs.104625$
Hence, Rs. 104625 are required to cover the floor with tiles .