A floor which measures 15 m - 8 m is to be laid with tiles measuring 50 cm - 25 cm- The number of tiles required isA- 1000B- 960C- 920D- 900

The correct option is B 960 Number of tiles required = Area of floor/Area of 1 tile = 1500 × 800/50 × 25 ...

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Standard VIII

Mathematics

Perimeter

A floor which...

Question

A floor which measures $15 m \times 8 m$ is to be laid with tiles measuring $50 c m \times 25 c m$ . The number of tiles required is ___

1000

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960

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920

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900

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Solution

The correct option is B
960

Number of tiles required $= \frac{Area of floor}{Area of 1 tile}$

$= \frac{1500 \times 800}{50 \times 25}$

$= 960$

Hence (b)

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A floor which measures 15 m×8 m is to be laid with tiles measuring 50 cm×25 cm. The number of tiles required is ___

The correct option is B 960 Number of tiles required =Area of floorArea of 1 tile =1500×80050×25 =960 Hence (b)

A floor which measures $15 m \times 8 m$ is to be laid with tiles measuring $50 c m \times 25 c m$ . The number of tiles required is ___

The correct option is B
960

Number of tiles required $= \frac{Area of floor}{Area of 1 tile}$

$= \frac{1500 \times 800}{50 \times 25}$

$= 960$

Hence (b)