A flooring tile has the shape of a parallelogram with base 24 cm and the corresponding height as 10 cm. The number of such tiles required to cover a floor of area 1080 $m^{2}$ are_____

34000

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44000

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45000

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54000

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Solution

The correct option is C 45000

$Area of parallelogram = Base \times Height$
$= 24 c m \times 10 c m = 240 sq.cm.$
$Required number of tiles = \frac{A r e a o f f l o o r}{A r e a o f 1 t i l e}$
$Required number of tiles = \frac{1080 \times 100 \times 100}{240} (converting sq. m to sq. cm)$
$= 45000 t i l e s$

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A flooring tile has the shape of a parallelogram with base 24 cm and the corresponding height as 10 cm. The number of such tiles required to cover a floor of area 1080 m2 are_____

The correct option is C 45000 Area of parallelogram=Base×Height =24 cm×10 cm=240 sq.cm. Required number of tiles=Area of floorArea of 1 tile Required number of tiles=1080×100×100240 (converting sq. m to sq. cm) =45000 tiles

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