A flooring tile has the shape of a rectangle whose dimensions are 10 cm - 6 cm- How many such tiles are required to cover a floor of area 30 - 50 cm 2 - If required you can split the tiles in whatever way you want to fill up the corners-A- 20 tilesB- 25 tilesC- 35 tilesD- 50 tiles

The correct option is B 25 tiles Number of tiles required = area of the floor/area of one tile = (30 × 50)/(10 × 6) = 25 tiles ...

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Byju's Answer

Standard VIII

Mathematics

Identifying Shapes and Areas of Different Regular Figures

A flooring ti...

Question

A flooring tile has the shape of a rectangle whose dimensions are 10cm × 6cm. How many such tiles are required to cover a floor of area 30 × 50 cm²? (If required you can split the tiles in whatever way you want to fill up the corners).

20 tiles

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25 tiles

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35 tiles

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50 tiles

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Solution

The correct option is B
25 tiles

Number of tiles required
= $\frac{a r e a o f t h e f l o o r}{a r e a o f o n e t i l e}$
= $\frac{(30 \times 50)}{(10 \times 6)}$
= 25 tiles

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A flooring tile has the shape of a rectangle whose dimensions are 10cm × 6cm. How many such tiles are required to cover a floor of area 30 × 50 cm2? (If required you can split the tiles in whatever way you want to fill up the corners).

The correct option is B 25 tiles Number of tiles required = area of the floorarea of one tile = (30×50)(10×6) = 25 tiles

A flooring tile has the shape of a rectangle whose dimensions are 10cm × 6cm. How many such tiles are required to cover a floor of area 30 × 50 cm²? (If required you can split the tiles in whatever way you want to fill up the corners).

The correct option is B
25 tiles

Number of tiles required
= $\frac{a r e a o f t h e f l o o r}{a r e a o f o n e t i l e}$
= $\frac{(30 \times 50)}{(10 \times 6)}$
= 25 tiles