A flow of $10^{6}$ electrons per second in a conducting wire constitutes a flow of current.

1.6 \times 10^{- 15} A

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1.6 \times 10^{- 11} A

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1.6 \times 10^{- 12} A

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1.6 \times 10^{- 19} A

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1.6 \times 10^{- 13} A

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Solution

The correct option is E $1.6 \times 10^{- 13} A$
Given, $n = 10^{6}$ electron per second
We know that, $q = n e$
$q = 10^{6} \times 1.6 \times 10^{- 19} C$
Now, as the flow charge is
$16 \times 10^{- 13}$ coulomb per second
So, $i = 1.6 \times 10^{- 13} A$ .

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A flow of 106 electrons per second in a conducting wire constitutes a flow of current.

The correct option is E 1.6×10−13AGiven, n=106 electron per secondWe know that, q=neq=106×1.6×10−19CNow, as the flow charge is16×10−13 coulomb per secondSo, i=1.6×10−13A.

A flow of $10^{6}$ electrons per second in a conducting wire constitutes a flow of current.

The correct option is E $1.6 \times 10^{- 13} A$
Given, $n = 10^{6}$ electron per second
We know that, $q = n e$
$q = 10^{6} \times 1.6 \times 10^{- 19} C$
Now, as the flow charge is
$16 \times 10^{- 13}$ coulomb per second
So, $i = 1.6 \times 10^{- 13} A$ .