A flow of 10 $^{7}$ electrons per second in a conducting wire constitutes a current of

1.6 \times 10^{- 26} A

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1.6 \times 10^{26} A

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1.6 \times 10^{- 12} A

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1.6 \times 10^{12} A

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Solution

The correct option is C $1.6 \times 10^{- 12} A$
We know that $I = Q / t$
$Q = 10^{7} \times 1.6 \times 10^{- 19}$ which is flowing per second in a conducting wire hence $I = 1.6 \times 10^{- 12} A$

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A flow of 107 electrons per second in a conducting wire constitutes a current of

The correct option is C 1.6×10−12AWe know that I=Q/tQ=107×1.6×10−19 which is flowing per second in a conducting wire hence I=1.6×10−12A

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The correct option is C $1.6 \times 10^{- 12} A$
We know that $I = Q / t$
$Q = 10^{7} \times 1.6 \times 10^{- 19}$ which is flowing per second in a conducting wire hence $I = 1.6 \times 10^{- 12} A$