Question

A fluid container containing a liquid of density $\rho$ is accelerating upward with the acceleration $a$ along the inclined plane of inclination $\alpha$ as shown. Then the angle of inclination $\theta$ of the free surface is _____.

Answer 1

$\tan \theta =\frac{a}{g_{effective}}\tan \theta =\frac{a}{g\cos \alpha }\theta ={\tan }^{-1}\left(\frac{a}{g\cos \alpha }\right)$