    Question

# A fluid while flowing through a tube as shown passes through points A and B. Find the velocity of the fluid at point B. A
415 m/s
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B
115 m/s
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C
215 m/s
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D
815 m/s
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Solution

## The correct option is D √815 m/sAccording to question On applying equation of continuity at point 1 and 2, A1v1=A2v2 ⇒v1=A2v2A1=2×v24 ⇒v1=v22.........(1) On applying bernoulli's equation at point 1 and 2, P1+ρgh1+12ρv21=P2+ρgh2+12ρv22 Since height is same at both the points. ⇒P1−P2=12ρ(v22−v21) P1−P2=12ρ(v22−v224) [ from (1) ] P1−P2=38ρv22............(2) Also, P1−P2=ρgho [ Pressure difference in column ] P1−P2=ρg×0.02 [ho=2 cm=0.02 m] P1−P2=15ρ..........(3) From (2) and (3), 38ρv22=15ρ ⇒v2=√815 m/s Speed of water at point B is √815 m/s  Suggest Corrections  0      Similar questions  Explore more