A fly flies from a point P(0,2,5) to the point Q(3,1,6). The magnitude of displacement covered by it is
A
√11
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B
√7
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C
√13
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D
√10
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Solution
The correct option is A√11 Given, the two points where fly flies, so representing them vectorially we have →P=2^j+5^k, and →Q=3^i+^j+6^k Thus, the displacement covered by it is −−→QP=→Q−→P ⇒(3−0)^i+(1−2)^j+(6−5)^k=3^i−^j+^k ⇒|−−→QP|=√32+(−1)2+12=√11