A fly flies from a point P(0,4,6) to the point Q(2,1,4). The magnitude of displacement covered by it is
A
√7
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B
√17
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C
√13
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D
√10
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Solution
The correct option is B√17 Given, the two points where fly flies, so representing them vectorially we have →P=4^j+6^k, and →Q=2^i+^j+4^k
Thus, the displacement covered by it is −−→PQ=→Q−→P ⇒(2−0)^i+(1−4)^j+(4−6)^k=2^i−3^j−2^k ⇒|−−→QP|=√22+(−3)2+(−2)2=√17