A flyback converter has following parameters -Vs - 24 V- N1-N2 - 3 C - 200 - FLm - 500 - H- R - 5- f - 25 kHz-The critical value of magnetizing inductor for output voltage of 10 V will be - H-

Layout of flyback converter V_0 = V_s ( α/1 α )N_2/N_1 10 = 24 ( α/1 α )1/3 ⇒ nbsp;1/α 1 = 0.8 α nbsp;= 0.555 V_0I_0 = V_sI_s I_0 = V_0/R = 10/5 = 2A ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Other

Discontinuous Mode Analysis of Boost Regulator

A flyback con...

Question

A flyback converter has following parameters :

$V_{s} = 24 V,$ $\frac{N_{1}}{N_{2}} = 3$ $C = 200 μ F$

$L_{m} = 500 μ H,$ $R = 5 Ω$ $f = 25 k H z .$

The critical value of magnetizing inductor for output voltage of 10 V will be ___ $μ H$ .

Open in App

Solution

Layout of flyback converter

$V_{0} = V_{s} (\frac{α}{1 - α}) \frac{N_{2}}{N_{1}}$

$10 = 24 (\frac{α}{1 - α}) \frac{1}{3}$

$\Rightarrow \frac{1}{α} - 1 = 0.8$

$α = 0.555$

$V_{0} I_{0} = V_{s} I_{s}$

$I_{0} = \frac{V_{0}}{R} = \frac{10}{5} = 2 A$

$I_{L m} = \frac{I_{s}}{α} = \frac{10 \times 2}{24} \times \frac{1}{0.555} = 1.501 A$

$I_{L m i n} = I_{L m} - \frac{Δ I_{i n}}{2}$

or $\frac{α V_{s}}{2 f L_{m c}} = 1.501$

$L_{m c} = 177.6 μ H$

Suggest Corrections

Similar questions

Q. A buck-boost converter has the following parameters:

V_{s}

= 28 V, D = 0.3, R = 5

Ω

,
L = 20

μ

H, C = 90

μ

F, f = 80 kHz
The output voltage of the converter and average current through inductor will be respectively

Q. A boost converter has an input voltage of

V_{S} = 5 V

. The average output voltage

V_{0} = 15 V

and the average load current

I_{0} = 0.5 A

. The switching frequency is 25 kHz. If

L = 150 μ H a n d C = 220 μ F

, then the peak inductor current will be ___________A

Q. A buck converter has following specification :

V_{s} = 24 V

L = 200 μ H,

R = 20 Ω

C = 1000 μ F

f = 10 k H z,

D = 0.4

The value of average output voltage will be ___V. (Answer up to three decimal places)

Q. A buck boost converter is operating at 20 kHz with inductor L = 50

μ

H. The output capacitor is sufficiently large and source voltage

V_{d} = 15 V .

The output is to be regulated at 10 V and the converter is supplying at load of 10 W. The duty ratio and mode of conduction of converter respectively will be

Q. Given

V_{s} = 20 V, V_{0} = 50 V, R = 50 Ω, L = 20 μ H, D = 0.5.

The converter will operate at a switching frequency of ____ kHz.

Join BYJU'S Learning Program

A flyback converter has following parameters : Vs=24V, N1N2=3 C=200 μF Lm=500 μH, R=5Ω f=25 kHz. The critical value of magnetizing inductor for output voltage of 10 V will be ___ μH.

Layout of flyback converter V0=Vs(α1−α)N2N1 10=24(α1−α)13 ⇒1α−1=0.8 α=0.555 V0I0=VsIs I0=V0R=105=2A ILm=Isα=10×224×10.555=1.501A ILmin=ILm−ΔIin2 or αVs2fLmc=1.501 Lmc=177.6 μH

A flyback converter has following parameters :

$V_{s} = 24 V,$ $\frac{N_{1}}{N_{2}} = 3$ $C = 200 μ F$

$L_{m} = 500 μ H,$ $R = 5 Ω$ $f = 25 k H z .$

The critical value of magnetizing inductor for output voltage of 10 V will be ___ $μ H$ .