Question

A flywheel of moment of inertia $0.32kg-m^2$ is rotated steadily at 120 rad/sec by an electric motor. The kinetic energy of the flywheel is

• A. 4608 J
• B. 1152 J
• C. 2304 J
• D. 6912 J

Answer 1

The correct option is C 2304 J

Kinetic energy, K.E. $=\frac{1}{2}I{\omega }^2=\frac{1}{2}\left(0.32\right)(120{)}^2=2304J.$