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Question

A football is kicked with a velocity of 20 m/s at an angle of 45 with the horizontal. Find the maximum height it reaches.


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Solution

At the highest point, uy = 0. Using the equation
v2y=u2y2gy,
0=(102ms)22×(10ms2)H
Or, H = 10m.
Thus, The maximum height reached is 10 m.


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