A football is kicked with a velocity of 20 m/s at an angle of 45∘ with the horizontal. Find the maximum height it reaches.
At the highest point, uy = 0. Using the equation
v2y=u2y−2gy,
0=(10√2ms)2−2×(10ms2)H
Or, H = 10m.
Thus, The maximum height reached is 10 m.