A football player kicks a $0.25 k g$ ball and imparts it a velocity of $10 m / s$ . The contact between foot and the ball is only $\frac{1}{50}$ th of a second. The kicking force is

250 N

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125 N

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0 N

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3.78 N

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Solution

The correct option is B $125 N$
Force = $\frac{△ P}{△ t}$ (Newtons 2nd law)

$F = \frac{m △ V}{△ f} = \frac{m (V_{f} - V_{i})}{△ f}$

Force, $m = 0.25 k g$

and $V_{f} = 10 m / s, V_{i} = 0 m / s$

$∴ F = \frac{(0.25) (10 - 0)}{\frac{1}{50}}$

$F = 0.25 (500)$

$F = 25 \times 5$

$F = 125 N$

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A football player kicks a 0.25kg ball and imparts it a velocity of 10m/s. The contact between foot and the ball is only 150th of a second. The kicking force is

The correct option is B 125NForce = △P△t (Newtons 2nd law)F=m△V△f=m(Vf−Vi)△fForce, m=0.25kgand Vf=10m/s,Vi=0m/s∴F=(0.25)(10−0)150F=0.25(500)F=25×5F=125N

A football player kicks a $0.25 k g$ ball and imparts it a velocity of $10 m / s$ . The contact between foot and the ball is only $\frac{1}{50}$ th of a second. The kicking force is