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A football te...

Question

A football team gains 3 and 4 points for successive 2 days and loses 5 points on the third day. Find the total points scored by the team by tree diagram.
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Solution

The correct option is A 2
Given,
Team gains 3 and 4 points on the first day and loses 5 points on the third day $= 3 + 4 - 5 = 2$

Tree Diagram

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Q. A football team gains 3 and 4 points for successive 2 days and loses 5 points on the third day. Find the total points scored by the team and also represent this in the tree diagram.

Football teams $T_{1}$ and $T_{2}$ have to play two games against each other. It is assumed that the outcomes of the two games are independent. The probabilities of $T_{1}$ winning, drawing and losing a game against $T_{2}$ are $\frac{1}{2}, \frac{1}{6}$ and $\frac{1}{3}$ , respectively. Each team gets 3 points for a win, 1 point for a draw and 0 points for a loss in a game. Let $X$ and $Y$ denote the total points scored by teams $T_{1}$ and $T_{2}$ , respectively, after two games.

$P (X > Y)$ is

Football teams $T_{1}$ and $T_{2}$ have to play two games against each other. It is assumed that the outcomes of the two games are independent. The probabilities of $T_{1}$ winning, drawing and losing a game against $T_{2}$ are $\frac{1}{2}, \frac{1}{6}$ and $\frac{1}{3}$ , respectively. Each team gets 3 points for a win, 1 point for a draw and 0 points for a loss in a game. Let $X$ and $Y$ denote the total points scored by teams $T_{1}$ and $T_{2}$ , respectively, after two games.

$P (X > Y)$ is

Q. Football teams

T_{1}

T_{2}

have to play two games against each other. It is assumed that the outcomes of the two games are independent. The probabilities of

T_{1}

winning, drawing and losing a game against

T_{2}

\frac{1}{2}, \frac{1}{6}

\frac{1}{3},

respectively. Each team gets

3

points for a win,

1

point for a draw and

0

point for a loss in a game. Let

X

Y

denote the total points scored by teams

T_{1}

T_{2},

respectively, after two games.

P (X = Y)

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