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Question

A footpath of uniform width runs around the inside of a rectangular field 12 m long and 14 m wide. If the path occupies 56 m2, the second degree equation from which we can find the width of the path is ______.(Take width = x)


A

3x252x+56=0

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B

4x252x+58=0

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C

4x254x+56=0

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D

4x252x+56=0

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Solution

The correct option is D

4x252x+56=0



Area of outer rectangle =12×14 m2=168 m2

Width of the footpath= x m

Area of inner rectangle=(122x)(142x) m2=4x252x+168 m2

Area of footpath = Area of outer rectangle - Area of inner rectangle

56=168(4x252x+168)

56=1684x2+52x168

56=4x2+52x

4x252x+56=0


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