(a) For the complex [Fe(CN)6]3−, write the hybridization type, magnetic character and spin nature of the complex. (Atomic number : Fe=26). (b) Draw one of the geometrical isomers of the complex [Pt(en)2Cl2]2+ which is optically active.
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Solution
(a) Atomic number of Fe is 26.
Electronic configuration of Fe = [Ar]3d64s2
Now, electronic configuration of Fe3+ = [Ar]3d54s0
So, its electronics and hybridisation is shown in figure 1.
So, hybridisation is d2sp3. Since, it has an unpaired electron so its magnetic character is paramagnetic. It is low spin complex.
(b). cis isomer of [Pt(en)2Cl2]2+ is optically active which is shown in figure 2.