1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A force 10 N acts tangentially at the highest point of a solid sphere of mass 10 kg kept on a rough horizontal plane. If the sphere rolls without slipping, find the acceleration of the centre of the sphere (in m/s2).

A
107
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
710
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
35
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
53
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is A 107 The sphere will have a tendency to slip towards left at the point of contact, thus friction will act rightwards as shown. Since the sphere is rolling without slipping, a=αR . . . (1) From ∑→Fext=m→acom F+f=ma ...(2) and from →τextcom=Icom→α −F×R+f×R=−25mR2×α ⇒F−f=25mRα ...(3) From (1), (2) & (3) 2F=ma+25ma=75ma ⇒a=10F7m=10×107×10=107 m/s2

Suggest Corrections
0
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program