Question

A force $240N$ acts normally on the surface of the area $6.0\times {10}^{-2}{m}^2$. Calculate the pressure.

Answer 1

$$\begin{gathered} Step1:-Givendata, \\ F=240N \\ A=6.0\times {10}^{-2}{m}^2 \\ Tofind=Pressure\left(P\right) \\ Step2:-Weknownthat, \\ Formula,P=\frac{F}{A} \\ Step3:-Solution, \\ \Rightarrow P=\frac{F}{A} \\ \Rightarrow P=\frac{240}{6.0\times {10}^{-2}} \\ \Rightarrow P=\frac{40}{{10}^{-2}} \\ \Rightarrow P=40\times {10}^{2}Pa \\ or \\ \Rightarrow P=4\times {10}^{3}Pa \\ Step4:-Totalpressureonthesurfaceis4\times {10}^{3}Pa. \end{gathered}$$