A force (4^i+^j−2^k)N acting on a body maintains its velocity at (2^i+3^j−^k)m/s. The power exerted is
A
15W
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B
13W
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C
12W
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D
20W
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Solution
The correct option is B13W We have force →F=(4^i+^j−2^k)N Velocity,→v=(2^i+3^j−^k)m/s Therefore, Power is given by P=→F.→v=(4^i+^j−2^k).(2^i+3^j−^k) ⇒P=(8+3+2)W ⇒P=13W