A force act for 0.1 s on a body of mass of 2.0kg in Italy at rest . The force in then withdraw and the body moves with a velocity of 2ms-1 . Find the magnitude of force.

Open in App

Solution

F=ma
a=v/t
therefore,
F=mv/t
22/0.1
ans=40N

Suggest Corrections

Similar questions

Q. A force acts for 1 s on a body of mass 2.0 kg initially at rest. The force is then withdrawn and the body attains a velocity of 2 m/s. Find the magnitude of the force.

Q. A body of mass

10 kg

is moving with a constant velocity

10 m/s

. When a constant force acts for

4 s

on it, it moves with a velocity

2 m/s

in the opposite direction. The magnitude of force acting on the body is

Q. A force of

25 N

acts on a body at rest for

0.2 s

and a force of

70 N

acts for the next

0.1 s

in opposite direction. If the final velocity of the body is

5 m s^{- 1}

, the mass of the body is:

A force of 25N acts on a body at rest for 0.2s and a force of 70N act for next 0.1s in opposite direction. If the final velocity of the body is 5m/s the mass of the body is?

Join BYJU'S Learning Program

A force act for 0.1 s on a body of mass of 2.0kg in Italy at rest . The force in then withdraw and the body moves with a velocity of 2ms-1 . Find the magnitude of force.

F=m*a a=v/t therefore, F=mv/t 2*2/0.1 ans=40N

F=ma
a=v/t
therefore,
F=mv/t
22/0.1
ans=40N