A force acting on a particle varies with the displacement x as F=ax−bx2. Where a=1N/m and b=1N/m2. The work done by this force for the first one meter (F is in newtons, x is in meters) is :
A
16J
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B
26J
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C
36J
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D
Noneofthese
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Solution
The correct option is A16J W=∫x0Fdx=ax22−bx33 (since a=1; b=1) W=x22−x33 For x= 1 m W=12−13=16J