A force acts for $0.1 s$ on a body of mass $5 kg$ , which was initially at rest. The force is then withdrawn and the body continues to move with a velocity of $2 m/s$ . Find the magnitude of force.

30 N

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60 N

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100 N

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40 N

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Solution

The correct option is C $100 N$
Acceleration $= \frac{c h a n g e i n v e l o c i t y}{T i m e i n t e r v a l} = 20 {m/s}^{2}$

Force = Mass $\times$ Acceleration
Acceleration $= \frac{2}{0.1} = 20 {m/s}^{2}$
Force = mass $\times$ acceleration
Force $= 5 \times 20 = 100 N$

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A force acts for 0.1 s on a body of mass 5 kg, which was initially at rest. The force is then withdrawn and the body continues to move with a velocity of 2 m/s. Find the magnitude of force.

The correct option is C 100 NAcceleration =change in velocityTime interval=20 m/s2 Force = Mass × Acceleration Acceleration =20.1=20 m/s2 Force = mass × acceleration Force =5×20=100 N

A force acts for $0.1 s$ on a body of mass $5 kg$ , which was initially at rest. The force is then withdrawn and the body continues to move with a velocity of $2 m/s$ . Find the magnitude of force.

The correct option is C $100 N$
Acceleration $= \frac{c h a n g e i n v e l o c i t y}{T i m e i n t e r v a l} = 20 {m/s}^{2}$

Force = Mass $\times$ Acceleration
Acceleration $= \frac{2}{0.1} = 20 {m/s}^{2}$
Force = mass $\times$ acceleration
Force $= 5 \times 20 = 100 N$