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Standard IX

Physics

Second Law of Motion

A force acts ...

Question

A force acts for $0.2 s e c$ on an object having mass $1.4 k g$ initially at rest. The force stops to act but the object moves through $4 m$ in the next $2 s e c$ . Find the magnitude of the force?

11 N

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19 N

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14 N

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21 N

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Solution

The correct option is D 14 N
Given,

Average velocity, $v = \frac{distance}{time} = \frac{4}{2} = 2 m s^{- 1}$

Force = rate of change of momentum

$F = \frac{m v_{a v g}}{t i m e} = \frac{1.4 \times 2}{0.2} = 14 N$

Hence, force is $14 N$

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A force acts for 0.2sec on an object having mass 1.4kg initially at rest. The force stops to act but the object moves through 4m in the next 2sec. Find the magnitude of the force?

The correct option is D 14 NGiven, Average velocity, v=distancetime=42=2ms−1 Force = rate of change of momentum F=mvavgtime=1.4×20.2=14N Hence, force is 14N

A force acts for $0.2 s e c$ on an object having mass $1.4 k g$ initially at rest. The force stops to act but the object moves through $4 m$ in the next $2 s e c$ . Find the magnitude of the force?

The correct option is D 14 N
Given,

Average velocity, $v = \frac{distance}{time} = \frac{4}{2} = 2 m s^{- 1}$

Force = rate of change of momentum

$F = \frac{m v_{a v g}}{t i m e} = \frac{1.4 \times 2}{0.2} = 14 N$

Hence, force is $14 N$