A force acts on a body of mass 0.4 kg initially at rest for 10 seconds. After removal of the force, if the body moves 100m in 20 seconds, the force on that body is

0.1N

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0.20N

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0.3N

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0.4N

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Solution

The correct option is C 0.20N
Given $:$
Moves a distance of $100 m$
Time $= 20 s e c$
speed $= 5 m / s$
$m = 0.4 k g$
$v = 0$
$t = 10 s e c$
$v = 5 m / s$
$a = 0.5 m / s^{2}$
$F = m \times a$
$F = 0.4 \times 0.5 = 0.20 N$
Hence,
option $(B)$ is correct answer.

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A force acts on a body of mass 0.4 kg initially at rest for 10 seconds. After removal of the force, if the body moves 100m in 20 seconds, the force on that body is

The correct option is C 0.20NGiven:Moves a distance of 100mTime=20secspeed=5m/sm=0.4kgv=0t=10secv=5m/sa=0.5m/s2F=m×aF=0.4×0.5=0.20NHence,option (B) is correct answer.

The correct option is C 0.20N
Given $:$
Moves a distance of $100 m$
Time $= 20 s e c$
speed $= 5 m / s$
$m = 0.4 k g$
$v = 0$
$t = 10 s e c$
$v = 5 m / s$
$a = 0.5 m / s^{2}$
$F = m \times a$
$F = 0.4 \times 0.5 = 0.20 N$
Hence,
option $(B)$ is correct answer.