A force acts on a body of mass 3 kg such that its velocity changes from $4 m s^{- 1}$ to $10 m s^{- 1}$ . The change in momentum of the body is:

42 k g m s^{- 1}

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2 k g m s^{- 1}

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18 k g m s^{- 1}

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14 k g m s^{- 1}

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Solution

The correct option is A $18 k g m s^{- 1}$
Given, $m = 3 k g$ , $v_{1} = 4 m / s$ and $v_{2} = 10 m / s$
Change in momentum $= p_{2} - p_{1} = m v_{2} - m v_{2} = m (v_{2} - v_{1}) = 3 (10 - 4) = 18$ $k g$ $m s^{- 1}$

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