Question

A force equal to the weight of the body acts on a body for $t$ seconds. If the frictional force is equal to half the weight of the body the distance travelled in $t$ seconds is

• A. $g^2{t}^{2/4}$
• B. $g{t}^2/4$
• C. $gt/4$
• D. $g^{2}t/2$

Answer 1

The correct option is B $g{t}^2/4$

From the given conditions, we have:
$Mg-\frac{Mg}{2}=Ma$ where $M$ is the mass of the body
Therefore, $a=\frac{g}{2}$

Also, $S=\frac{a{t}^2}{2}$ $S=\frac{g{t}^2}{4}$