A force $F = 2^i + 3^j -^k$ acts at a point $(2, - 3, 1) .$ Then magnitude of torque about point $(0, 0, 2)$ will be:

6

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3 \sqrt{5}

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6 \sqrt{5}

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none of these

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Solution

The correct option is C $6 \sqrt{5}$
$∣ ∣ ∣ ∣ \begin{matrix} 1 & j & k 2 & - 3 & - 1 2 & 3 & - 1 \end{matrix} ∣ ∣ ∣ ∣$
$i (3 + 3) - j (- 2 + 2) + k (6 + 6)$
$T = 6 i^{i} + 12^k$
$| T | = \sqrt{6^{2} + 12^{2}} = \sqrt{36 + 144}$
$T = \sqrt{180} N m$
$T = 6 \sqrt{5} N m$

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Similar questions

\to F = 2^i + 3^j -^k

(2, - 3, 1)

(0, 0, 2)

A force $\to F = 2^i + 3^j -^k$ acts at a point (2, - 3, 1). Then magnitude of torque of this force about point (0, 0, 2) will be

F = 2^i + 3^j -^k

\to F = (^i + 2^j + 3^k) N

(4^i + 3^j -^k) m

(^i + 2^j +^k) m

\sqrt{x} N-m

x

\to F = 2^i - 3^j +^k

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