A force $F = (3 x^{2} + 2 x - 7) N$ acts on a $2 k g$ body as a result of which the body gets displaced from $x = 0$ to $x = 5 m$ . The work done by the force will be:

5 J

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70 J

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115 J

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270 J

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Solution

The correct option is C $115 J$
Given, $= 3 x^{2} + 2 x - 7, m a s s = 2 k g$

So the work-done $W = \int_{0}^{5} (3 x^{2} = 2 x - 7) d x = [x^{3} + x^{2} - 7 x]_{0}^{5} = [5^{3} + 5^{2} - 7 \times 5 = 115 J$

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A force F=(3x2+2x−7)N acts on a 2kg body as a result of which the body gets displaced from x=0 to x=5m. The work done by the force will be:

The correct option is C 115JGiven, =3x2+2x−7,mass=2kgSo the work-done W=∫50(3x2=2x−7)dx=[x3+x2−7x]50=[53+52−7×5=115J

A force $F = (3 x^{2} + 2 x - 7) N$ acts on a $2 k g$ body as a result of which the body gets displaced from $x = 0$ to $x = 5 m$ . The work done by the force will be:

The correct option is C $115 J$
Given, $= 3 x^{2} + 2 x - 7, m a s s = 2 k g$

So the work-done $W = \int_{0}^{5} (3 x^{2} = 2 x - 7) d x = [x^{3} + x^{2} - 7 x]_{0}^{5} = [5^{3} + 5^{2} - 7 \times 5 = 115 J$