A force F = 3i + 4j Newton acts on a particle which move from a position (2m , 3 m) to ( 3m, 0m). Then the work done is:

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Solution

Given Force,
$\to F = 3^i + 4^y$
Displacement of the particle, from given coordinates :
$Δ \to r = {\to r}_{f} - {\to r}_{i}$
$= (3^i + 0^j) - (2^i + 3^j)$
$\Rightarrow Δ \to r = (^i - 3^j) m$
So, work done by force
$w = \to F . A \to r$
$= (3^i + 4^j) . (^i - 3^j)$
$\Rightarrow w = - 9^j$

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