A force $F = (5^i + 3^j)$ newtons is applied over a particle which displaces it from its origin to the point $r = (2^i - 1^j)$ metres. The work done on the particle is

- 7 j o u l e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 13 j o u l e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 7 j o u l e s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+ 11 j o u l e s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $+ 7 j o u l e s$
Displacement $\to d = \to r$
Work done $\to F . \to d = \to F . \to r = (5^i + 3^j) (2^i - 1^j)$
$= 10 - 3 = 7 J$

Suggest Corrections

Similar questions

A force $F = (5^i + 3^j)$ newton is applied over a particle which displaces it from its origin to the point $r = (2^i - 1^j)$ metre. The work done on the particle is

Q. A force

F = (5^i + 3^j)

newton. Over a particle which displacement it from its origin to the point r

= (2^i + 1^j)

meters. The work done on the particle is

Q. A force

\to F = (5^i + 3^j + 2^k) N

is applied over a particle which displaces it from origin to the point

\to r = (2^i -^j) m

. The work done on the particle is

Q. A force

\to F = (5^i + 3^j + 2^k) N

is applied over a particle which displaces it from origin to the point

\to r = (2^i -^j) m

. The work done on the particle is

Q. A force-

\to F = (5^i + 3^j + 2^k) N

is applied over a particle which displaces it from its origin to the point

\to r = (2^i -^j) m

. The work done on the particle in joule is :

Join BYJU'S Learning Program

A force F=(5^i+3^j) newtons is applied over a particle which displaces it from its origin to the point r=(2^i−1^j) metres. The work done on the particle is

The correct option is B +7 joulesDisplacement →d=→rWork done →F.→d=→F.→r=(5^i+3^j)(2^i−1^j)=10−3=7J

A force $F = (5^i + 3^j)$ newtons is applied over a particle which displaces it from its origin to the point $r = (2^i - 1^j)$ metres. The work done on the particle is

The correct option is B $+ 7 j o u l e s$
Displacement $\to d = \to r$
Work done $\to F . \to d = \to F . \to r = (5^i + 3^j) (2^i - 1^j)$
$= 10 - 3 = 7 J$