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Byju's Answer
Standard XII
Physics
Electric Field Due to a Sphere and Thin Shell
A force F = (...
Question
A force F = (5i + 3j + 2k)N is applied over a particle which displaces it from in origin to the point r = (2i - j)m.Find the workdone on the particle in joule.
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Solution
Dear Student .
Here in this question the given data is ,
F
→
=
5
i
^
+
3
j
^
+
2
k
^
a
n
d
d
i
s
p
l
a
c
e
m
e
n
t
i
s
r
→
=
2
i
^
-
j
^
T
h
e
r
e
f
o
r
e
t
h
e
w
o
r
k
d
o
n
e
o
n
t
h
e
p
a
r
t
i
c
l
e
i
s
,
W
=
F
→
·
r
→
=
5
i
^
+
3
j
^
+
2
k
^
·
2
i
^
-
j
^
=
10
-
3
=
7
J
Regards
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Similar questions
Q.
A force
→
F
=
(
5
^
i
+
3
^
j
2
^
k
)
N
is applied over a partivle which displaces it from its origin to the point
→
r
=
(
2
^
i
−
^
j
)
m
. The work done on the particle in joules is then
Q.
A force
→
F
=
(
5
^
i
+
3
^
j
+
2
^
k
)
N
is applied over a particle which displaces it from origin to the point
→
r
=
(
2
^
i
−
^
j
)
m
. The work done on the particle is
Q.
A force
→
F
=
(
5
^
i
+
3
^
j
+
2
^
k
)
N
is applied over a particle which displaces it to a point having position vector
→
r
=
(
2
^
i
−
^
j
)
m
from origin. The work done on the particle (in
J
) is
Q.
A force
→
F
=
(
5
^
i
+
3
^
j
+
2
^
k
)
N
is applied over a particle which displaces it to a point having position vector
→
r
=
(
2
^
i
−
^
j
)
m
from origin. The work done on the particle (in
J
) is
Q.
A force
F
=
5
i
−
3
j
+
2
^
k
moves a particle from
r
1
=
2
i
+
7
j
+
4
^
k
to
r
2
=
5
^
i
+
2
^
j
+
8
^
k
⋅
Calculate the workdone:
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