Question

A force $F=(6i-8j)N,$ acts on a particle and displaces it over $4m$ along the X-axis and $6m$ along the Y-axis. The total work done during the two displacements is:

• A. $72J$
• B. $24J$
• C. $-24J$
• D. Zero

Answer 1

Answer: (C)

$-24J$

We can write S as=$4\hat{i}+6\hat{j}$

And given $F=6\hat{i}-8\hat{j}$N

And we can find work done as=$F.S$

Now , $Work$ =($6\hat{i}-8\hat{j}$). ($4\hat{i}+6\hat{j}$)

$Work=24-48$

$Work=-24J$