Question

A force $F$ acting on a particle varies with position $x$ as shown in figure. The workdone by this force in displacing the particle from $x=0$ to $x=2\text{m}$.

• A. $10\text{J}$
• B. $20\text{J}$
• C. $-20\text{J}$
• D. $-10\text{J}$

Answer 1

The correct option is A $10\text{J}$

While moving from $x=0$ to $x=2\text{m}$, displacement of particle and force acting on the particle both are along positive x direction.
$\therefore$ Work done is positive.
Workdone $\left(W\right)=$ Area under $F-x$ curve
$=\frac{1}{2}\left(2\right)\left(10\right)=10\text{J}$