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Question

A force F acting on a particle varies with position x as shown in figure. The work done by this force in displacing the particle from x=1 m to 1 m.


A
+20 J
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B
0 J
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C
20 J
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D
+10 J
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Solution

The correct option is B 0 J
While moving from x=1 m to x=0 m, the particle has a positive displacement, but the force acting on the particle is along x direction.
From x=0 to x=1 m,both displacement and force are along +x direction.
Work done (W)= Area under Fx graph = Area of tringle ODC - Area of tringle ABO
=12(10)×512×(0(1))×5=5252=0 J

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