A force F acting on a particle varies with the position x as shown in figure. Find the work done by this force in displacing the particle from x=0mtox=2m.
A
−10J
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B
10J
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C
5J
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D
−5J
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Solution
The correct option is B10J From x=0mtox=2m., displacement of particle and force acting on the particle both are along positive x-direction. Therefore, work done is positive and given by the area under F−x graph, or W=12(2)(10)=10J