A force F acts on a body and displaces it by a distance S in a direction at an angle θ with the direction of force. Write the expression for the work done by the force.
A
FSsinθ
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B
FScotθ
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C
FScosθ
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D
FStanθ
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Solution
The correct option is CFScosθ Here we are applying a force F at an angle of θ, if we resolve the force it becomes Fcosθ and Fsinθ.
We have displacement along Fcosθ
We know that work-done is the product of force and displacement along the direction of the force. Hence, workdone=Fcosθ∗S.