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Question

A force F acts on a body and displaces it by a distance S in a direction at an angle θ with the direction of force. Write the expression for the work done by the force.

A
F S sinθ
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B
F S cotθ
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C
F S cosθ
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D
F S tanθ
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Solution

The correct option is C F S cosθ
Here we are applying a force F at an angle of θ, if we resolve the force it becomes Fcosθ and Fsinθ.
We have displacement along Fcosθ
We know that work-done is the product of force and displacement along the direction of the force.
Hence,
work done=FcosθS.


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