A force F=−kx2(x≠0,(k) is a positive constant), acts on a particle in x direction. The work done by this force in displacing the particle from x=+a to x=+2a is
A
+k2a
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B
−ka
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C
ka
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D
−k2a
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Solution
The correct option is D−k2a Given variable force (F)=−kx2(k>0) Workdone by variable force on the particle to displace it from the position x=a to x=2a. W=∫x2x1Fxdx W=∫+2a+a−kx2dx=kx|+2a+a=−k2a