A force F=(^i+4^j)N acts on the block shown. The force of friction acting on the block is :
A
−^iN
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B
−18^iN
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C
−2.4^iN
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D
−3^iN
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Solution
The correct option is A−^iN
As given in fig. Normal force, N=(10−4)^j=6^j Maximum friction force, f=μN(−^i)=0.3×6(−^i)=1.8(−^i)) Maximum firctional force is f>1N , so the frictional force act only equal to the force in (+^i) direction but in opposite direction; f=1(−^iN).