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Question

A force F=(^i+4^j) N acts on the block shown. The force of friction acting on the block is :

A
^i N
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B
18 ^i N
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C
2.4 ^i N
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D
3 ^i N
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Solution

The correct option is A ^i N

As given in fig.
Normal force,
N=(104)^j=6^j
Maximum friction force,
f=μN(^i)=0.3×6(^i)=1.8(^i))
Maximum firctional force is f>1 N , so the frictional force act only equal to the force in (+^i) direction but in opposite direction;
f=1(^i N).

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