Question

A force F is acting on a body and its component along x-axis is 60 N. The Force F is inclined at an angle ${30}^{\circ }$ as shown. Determine F.

• A. $F=30\sqrt{3}N$
• B. $F=40\sqrt{3}N$
• C. $F=50\sqrt{3}N$
• D. $F=60\sqrt{3}N$

Answer 1

The correct option is B $F=40\sqrt{3}N$

Horizontal component of force = $F\cos \theta =60$
$F=\frac{60}{\cos \theta }=\frac{60}{\cos {30}^{\circ }}=40\sqrt{3}N$