Question

A force $F$ is acting on an object varies with distance $x$ is shown in the figure given below. The force is in $\text{N}$ and $x$ is in $\text{m}$. The work done by the force in moving the object from $x=0\text{to}x=6\text{m}$ is

• A. $4.5\text{J}$
• B. $13.5\text{J}$
• C. $9.0\text{J}$
• D. $18\text{J}$

Answer 1

The correct option is B $13.5\text{J}$

Work done will be area under $\text{F - x}$ curve
So, required work done = Area of given trapezium
$W=\frac{1}{2}\left(3\right)(3+6)=13.5\text{J}$