A force F is applied horizontally to a block A of mass $m_{1}$ which is in contact with a block B of mass $m_{2}$ , as shown in the figure. If the surfaces are frictionless, the force exerted by A on B is equal to

$\frac{m_{1} F}{m_{2}}$

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$\frac{m_{2} F}{m_{1}}$

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$\frac{m_{1} F}{m_{1} + m_{2}}$

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$\frac{m_{2} F}{m_{1} + m_{2}}$

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Solution

The correct option is D
$\frac{m_{2} F}{m_{1} + m_{2}}$

Acceleration of the system, $a = \frac{F}{m_{1} + m_{2}}$
Now, the force exerted by A on B is responsible for the acceleration of block B and is given by $F^{'} = m_{2} a = \frac{m_{2} F}{m_{1} + m_{2}}$ .
Hence, the correct choice is (d).

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A force F is applied horizontally to a block A of mass m1 which is in contact with a block B of mass m2, as shown in the figure. If the surfaces are frictionless, the force exerted by A on B is equal to

The correct option is D m2Fm1+m2 Acceleration of the system, a=Fm1+m2 Now, the force exerted by A on B is responsible for the acceleration of block B and is given by F′=m2a=m2Fm1+m2. Hence, the correct choice is (d).

A force F is applied horizontally to a block A of mass $m_{1}$ which is in contact with a block B of mass $m_{2}$ , as shown in the figure. If the surfaces are frictionless, the force exerted by A on B is equal to

The correct option is D
$\frac{m_{2} F}{m_{1} + m_{2}}$

Acceleration of the system, $a = \frac{F}{m_{1} + m_{2}}$
Now, the force exerted by A on B is responsible for the acceleration of block B and is given by $F^{'} = m_{2} a = \frac{m_{2} F}{m_{1} + m_{2}}$ .
Hence, the correct choice is (d).