A force $F$ is applied on a lawn mower at an angle of $60^{\circ}$ with the horizontal. If it moves through a distance $x$ in horizontal direction, the work done by the force is:

\frac{F x}{2}

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\frac{\sqrt{3} F x}{2}

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2 F x

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None of the above

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Solution

The correct option is A $\frac{F x}{2}$
$W . D = \to F . \to S = F . x c o s 60$
$= \frac{1}{2} F x$

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A force F is applied on a lawn mower at an angle of 60∘ with the horizontal. If it moves through a distance x in horizontal direction, the work done by the force is:

The correct option is A Fx2W.D=→F.→S=F.xcos60=12Fx

A force $F$ is applied on a lawn mower at an angle of $60^{\circ}$ with the horizontal. If it moves through a distance $x$ in horizontal direction, the work done by the force is:

The correct option is A $\frac{F x}{2}$
$W . D = \to F . \to S = F . x c o s 60$
$= \frac{1}{2} F x$