A force F is applied to a block of mass 4√3kg as shown in the diagram. What should be the maximum value of force so that the block does not move? (Take g=10m/s2)
A
10N
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B
40N
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C
80N
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D
90N
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Solution
The correct option is C80N F force will be having 2 components: Horizontal component will be Fcos60o and the vertical component will be Fsin60o
Balancing vertical forces, we have N=Fsin60∘+mg(1) Balancing Horizontal forces For the block not to move, we must have Fcos60∘=μN taking value of N from equation 1 Fcos60∘=μ(Fsin60∘+mg) F(12)=12√3[F(√32)+(4√3)(10)]N or F(1−12)=40N or F=80N